The clearwell at a 3 MGD plant is 102 feet in diameter and 20 feet deep. How many gallons of water can the tank hold?

To determine how many gallons of water the clearwell can hold, we start by calculating its volume using the formula for the volume of a cylinder:

[ V = \pi r^2 h ]

where ( V ) is the volume, ( r ) is the radius, and ( h ) is the height (or depth in this case) of the cylinder.

Given that the diameter of the clearwell is 102 feet, we can find the radius by dividing the diameter by 2:

[ r = \frac{102}{2} = 51 \text{ feet} ]

The depth of the clearwell is given as 20 feet, so we have:

• Radius ( r = 51 ) feet

• Height ( h = 20 ) feet

Now, substituting these values into the volume formula:

[ V = \pi (51)^2 (20) ]

Calculating ( (51)^2 ):

[ 51^2 = 2601 ]

Now, substituting this back into the volume equation:

[ V = \pi \times 2601 \times 20 ]

[ V = \pi \times 52020 ]

Calculating this gives