How many gallons of water will 2 basins hold, each 65 feet long, 15 feet deep, and 20 feet wide?

To find out how many gallons of water the two basins can hold, we first need to calculate the volume of one basin. The volume can be calculated using the formula for the volume of a rectangular prism, which is length × width × depth.

For one basin:

• Length = 65 feet

• Width = 20 feet

• Depth = 15 feet

Now, calculate the volume:

Volume of one basin = 65 ft × 20 ft × 15 ft

= 19,500 cubic feet.

Since there are two basins, we multiply the volume of one basin by 2:

Total volume = 19,500 cubic feet × 2 = 39,000 cubic feet.

Next, we need to convert the volume from cubic feet to gallons. The conversion factor is that 1 cubic foot is equivalent to approximately 7.48 gallons.

Now, convert the total volume to gallons:

Total volume in gallons = 39,000 cubic feet × 7.48 gallons/cubic foot

= 291,720 gallons.

Thus, the total amount of water that the two basins can hold is 291,720 gallons, making that the correct answer.